<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: Card Counting on Yablon/Red Dog ?</title>
	<atom:link href="http://www.the-red-dog-guide.com/card-counting-yablonin-red-dog.html/feed" rel="self" type="application/rss+xml" />
	<link>http://www.the-red-dog-guide.com/card-counting-yablonin-red-dog.html</link>
	<description>Online Red Dog games, site reviews, articles, news, shopping and other resources for fans of Red Dog Poker</description>
	<lastBuildDate>Tue, 24 Aug 2010 23:22:25 +0000</lastBuildDate>
	<generator>http://wordpress.org/?v=2.9.2</generator>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
		<item>
		<title>By: excel training</title>
		<link>http://www.the-red-dog-guide.com/card-counting-yablonin-red-dog.html/comment-page-1#comment-1857</link>
		<dc:creator>excel training</dc:creator>
		<pubDate>Tue, 24 Aug 2010 23:22:25 +0000</pubDate>
		<guid isPermaLink="false">http://www.the-red-dog-guide.com/red-dog-tips/red-dog-questions/applying-card-counting-on-the-card-game-called-yablonin-between-or-red-dog/#comment-1857</guid>
		<description>&lt;strong&gt;Online goedkope excel cursus en andere office trainingen...&lt;/strong&gt;

Veel kortingsbonnen om korting te krijgen bij veel online winkels...</description>
		<content:encoded><![CDATA[<p><strong>Online goedkope excel cursus en andere office trainingen&#8230;</strong></p>
<p>Veel kortingsbonnen om korting te krijgen bij veel online winkels&#8230;</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: zadignose</title>
		<link>http://www.the-red-dog-guide.com/card-counting-yablonin-red-dog.html/comment-page-1#comment-466</link>
		<dc:creator>zadignose</dc:creator>
		<pubDate>Thu, 31 Dec 2009 18:40:46 +0000</pubDate>
		<guid isPermaLink="false">http://www.the-red-dog-guide.com/red-dog-tips/red-dog-questions/applying-card-counting-on-the-card-game-called-yablonin-between-or-red-dog/#comment-466</guid>
		<description>It&#039;s an interesting question.  I haven&#039;t put any deep thought into this game, but you&#039;ve got me thinking now.  Certainly, if there was no such thing as a &quot;raise,&quot; and the payoffs didn&#039;t vary based on the spread between cards, there would be no point to counting cards.  No deck composition would be better or worse than any other, since your odds of winning are the same regardless (when you place the initial bet before the cards are dealt out).

It seems you&#039;d improve your chances with lots of &quot;medium&quot; cards in the deck.  If there were very few &quot;medium&quot; cards, then the payoff odds would be worse, without affecting your chances of winning (wide spreads like K-5 would be dealt, which only pay 1:1, but the lack of medium cards mean you&#039;re no more likely to win these).  Meanwhile, knowing that there was a preponderance of medium cards would give you an occasional good raise opportunity after seeing a wide spread like 4-J, and the payoff odds would sometimes be improved in the situations where you hit a 9 right in the middle of an 8-T (you&#039;re still upset when the dealer puts down 8-T, but you&#039;re *less* upset than you&#039;d be if there weren&#039;t lots of 9s in the deck).

Therefore, it seems you would want to track &quot;medium&quot; cards vs. &quot;extreme&quot; cards.  Maybe a counting system like

7,8, or 9...................-2
A or K......................+2
2 or Q......................+1

Meaning you count -2 for every exposed 7, 8, or 9, etcetera.  Or maybe:

7,8, or 9..................-4
A,2, Q or K.............+3

But that seems harder to track.

Computation is needed to determine what to do with this information.  (also, as noted in the previous reply, you could get a more precise measure of what a &quot;correct&quot; count should look like).  Most important is to answer this:  &quot;How probable is it that any edge gained from counting cards will be sufficient to overcome the house edge?&quot;

If I have any more insights, I&#039;ll edit with whatever I find.

Edit:  Oops, Ace is one, so I changed above accordingly.  Reversed signs that were mixed up.</description>
		<content:encoded><![CDATA[<p>It&#8217;s an interesting question.  I haven&#8217;t put any deep thought into this game, but you&#8217;ve got me thinking now.  Certainly, if there was no such thing as a &#8220;raise,&#8221; and the payoffs didn&#8217;t vary based on the spread between cards, there would be no point to counting cards.  No deck composition would be better or worse than any other, since your odds of winning are the same regardless (when you place the initial bet before the cards are dealt out).</p>
<p>It seems you&#8217;d improve your chances with lots of &#8220;medium&#8221; cards in the deck.  If there were very few &#8220;medium&#8221; cards, then the payoff odds would be worse, without affecting your chances of winning (wide spreads like K-5 would be dealt, which only pay 1:1, but the lack of medium cards mean you&#8217;re no more likely to win these).  Meanwhile, knowing that there was a preponderance of medium cards would give you an occasional good raise opportunity after seeing a wide spread like 4-J, and the payoff odds would sometimes be improved in the situations where you hit a 9 right in the middle of an 8-T (you&#8217;re still upset when the dealer puts down 8-T, but you&#8217;re *less* upset than you&#8217;d be if there weren&#8217;t lots of 9s in the deck).</p>
<p>Therefore, it seems you would want to track &#8220;medium&#8221; cards vs. &#8220;extreme&#8221; cards.  Maybe a counting system like</p>
<p>7,8, or 9&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.-2<br />
A or K&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.+2<br />
2 or Q&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.+1</p>
<p>Meaning you count -2 for every exposed 7, 8, or 9, etcetera.  Or maybe:</p>
<p>7,8, or 9&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;-4<br />
A,2, Q or K&#8230;&#8230;&#8230;&#8230;.+3</p>
<p>But that seems harder to track.</p>
<p>Computation is needed to determine what to do with this information.  (also, as noted in the previous reply, you could get a more precise measure of what a &#8220;correct&#8221; count should look like).  Most important is to answer this:  &#8220;How probable is it that any edge gained from counting cards will be sufficient to overcome the house edge?&#8221;</p>
<p>If I have any more insights, I&#8217;ll edit with whatever I find.</p>
<p>Edit:  Oops, Ace is one, so I changed above accordingly.  Reversed signs that were mixed up.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: sandynlily</title>
		<link>http://www.the-red-dog-guide.com/card-counting-yablonin-red-dog.html/comment-page-1#comment-465</link>
		<dc:creator>sandynlily</dc:creator>
		<pubDate>Tue, 29 Dec 2009 17:27:47 +0000</pubDate>
		<guid isPermaLink="false">http://www.the-red-dog-guide.com/red-dog-tips/red-dog-questions/applying-card-counting-on-the-card-game-called-yablonin-between-or-red-dog/#comment-465</guid>
		<description>Card counting systems gauge assign point to cards that are proportional to their &quot;effect of removal&quot; on the EV of the game being played.

For blackjack cards 2-7 have an effect of decreasing the house edge when removed, and the rest increase it.

So in the game of blackjack point values are assigned negative and positive number to those two groups.


For another game entirely, the effect of removal will be different, so point assignments would need to be different.  This means that blackjack card counting systems would not be ideal.

It may be logical, that the cards that are most important in this game are the cards that are MOST likely to fall between two cards, i would imagine that cards 7,8,9 would fall between two other cards values more often than any other cards, or perhaps the cards that represent the end of the spectrum would be most valuable, since they offer you the best ability to predict when the cards will fall between them.

You have to gauge what kind of effect each card has when its removed form the game in comparison to each other card and assign point accordingly, then use a computer to simulate at what count enough cards are removed to overcome the house advantage.

I know nothing about the game in question, but other games are beatable by card counting, blackjack is just the most common.

Some games are not beatable by card coutning, and i feel this may be the case for this one unfortunately from what i understand about it.

-----Edit, after further research into the game, i found that the house edge lies in the shorting of payouts based on their odds, this would suggest that the game may be beatable if the player can detect a large anough change in the probibilities of the game , I also foudn the house edge to be somewhat small.

I feel that it is vulnerable to card counting for the main aspect of the game using a multi paramiter count that incorperates more than two card groups.

I also feel that the payout for ties when the dealer draws a thrid card is particularly vulnerable.</description>
		<content:encoded><![CDATA[<p>Card counting systems gauge assign point to cards that are proportional to their &#8220;effect of removal&#8221; on the EV of the game being played.</p>
<p>For blackjack cards 2-7 have an effect of decreasing the house edge when removed, and the rest increase it.</p>
<p>So in the game of blackjack point values are assigned negative and positive number to those two groups.</p>
<p>For another game entirely, the effect of removal will be different, so point assignments would need to be different.  This means that blackjack card counting systems would not be ideal.</p>
<p>It may be logical, that the cards that are most important in this game are the cards that are MOST likely to fall between two cards, i would imagine that cards 7,8,9 would fall between two other cards values more often than any other cards, or perhaps the cards that represent the end of the spectrum would be most valuable, since they offer you the best ability to predict when the cards will fall between them.</p>
<p>You have to gauge what kind of effect each card has when its removed form the game in comparison to each other card and assign point accordingly, then use a computer to simulate at what count enough cards are removed to overcome the house advantage.</p>
<p>I know nothing about the game in question, but other games are beatable by card counting, blackjack is just the most common.</p>
<p>Some games are not beatable by card coutning, and i feel this may be the case for this one unfortunately from what i understand about it.</p>
<p>&#8212;&#8211;Edit, after further research into the game, i found that the house edge lies in the shorting of payouts based on their odds, this would suggest that the game may be beatable if the player can detect a large anough change in the probibilities of the game , I also foudn the house edge to be somewhat small.</p>
<p>I feel that it is vulnerable to card counting for the main aspect of the game using a multi paramiter count that incorperates more than two card groups.</p>
<p>I also feel that the payout for ties when the dealer draws a thrid card is particularly vulnerable.</p>
]]></content:encoded>
	</item>
</channel>
</rss>
